The GetListPos() function retrieves the current position index from the queried linked list.
FACTS:
* Don't know what a linked list is ?, make sure you read the LinkedLists tutorial then.
Mini Tutorial:
This example creates a list of three people, then runs through and manually displays each persons name and their list position.
; Declare the "Person" user defined type.
Type Person
; These Fields will hold this persons name
FirstName$
SurName$
EndType
; Dimension the Friends variable of type Person,
; with linked list support
Dim Friends As Person List
; Add a person (Billy) to Friends list
Friends= New Person
Friends.FirstName$ ="Billy"
Friends.Surname$ ="Citizen"
; Add another person (Sally) to Friends list
Friends= New Person
Friends.FirstName$ ="Sally"
Friends.Surname$ ="Stevens"
; Add another person (Sally) to Friends list
Friends= New Person
Friends.FirstName$ ="Olivia"
Friends.Surname$ ="Dude"
; Aak the list what cell is at the front/start of the list
ThisLInk=GetListFirst(Friends())
;Enter a while loop providing the link is above 0
While ThisLink>0
; Manually Set our Current position in the list
SetListPos Friends(),ThisLInk
; Display this persons current position.
Print "List Position="+Str$(GetListPos(Friends()))
; Display this persons name
Print Friends.FirstName$+" "+Friends.Surname$
Print ""
; Ask the list for the Next LINK to move forward through
; the list.
ThisLink=GetListNext(Friends())
EndWhile
; display the screen and wait for a key press
Sync
WaitKey
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This example would output.
List Position=3
Olivia Dude
List Position=2
Sally Stevens
List Position=1
Billy Citizen
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